4y^2+19xy-5x^2=0

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Solution for 4y^2+19xy-5x^2=0 equation: 


Simplifying
4y2 + 19xy + -5x2 = 0

Reorder the terms:
19xy + -5x2 + 4y2 = 0

Solving
19xy + -5x2 + 4y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-5x + -1y)(x + -4y) = 0


Subproblem 1
Set the factor '(-5x + -1y)' equal to zero and attempt to solve:

Simplifying
-5x + -1y = 0

Solving
-5x + -1y = 0

Move all terms containing x to the left, all other terms to the right.

Add 'y' to each side of the equation.
-5x + -1y + y = 0 + y

Combine like terms: -1y + y = 0
-5x + 0 = 0 + y
-5x = 0 + y
Remove the zero:
-5x = y

Divide each side by '-5'.
x = -0.2y

Simplifying
x = -0.2y

Subproblem 2
Set the factor '(x + -4y)' equal to zero and attempt to solve:

Simplifying
x + -4y = 0

Solving
x + -4y = 0

Move all terms containing x to the left, all other terms to the right.

Add '4y' to each side of the equation.
x + -4y + 4y = 0 + 4y

Combine like terms: -4y + 4y = 0
x + 0 = 0 + 4y
x = 0 + 4y
Remove the zero:
x = 4y

Simplifying
x = 4y
Solution
x = {-0.2y, 4y}

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